If y=(x 2 +6x+8) 1/2 , then show that: (1+iy) 1/2 +(1-iy) 1/2 = [2(x+y)] 1/2

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Deepak Kumar Shringi · Answer

here 1+y 2 =(x+3) 2 use this and go through to get the answer

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If y=(x 2 +6x+8) 1/2 , then show that: (1+iy) 1/2 +(1-iy) 1/2 = [2(x+y)] 1/2

If y=(x²+6x+8)^1/2, then show that:
(1+iy)^1/2 +(1-iy)^{1/2 = [2(x+y)]}^1/2

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If y=(x 2 +6x+8) 1/2 , then show that: (1+iy) 1/2 +(1-iy) 1/2 = [2(x+y)] 1/2

If y=(x2+6x+8)1/2, then show that:(1+iy)1/2 +(1-iy)1/2 = [2(x+y)]1/2

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If y=(x²+6x+8)^1/2, then show that:
(1+iy)^1/2 +(1-iy)^{1/2 = [2(x+y)]}^1/2