if the three points (a,b) ,(a+lambda cos alpha, b+lambda sin alpha) , (a+lamda cos beta, b+sin beta) are the vertices of an equilateral triangle, then prove that|alpha-beta|=pie/3

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Saurabh Koranglekar · Answer

Dear student Property of equilateral triangle is all sides are equal using that we can prove the needful Regards

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if the three points (a,b) ,(a+lambda cos alpha, b+lambda sin alpha) , (a+lamda cos beta, b+sin beta) are the vertices of an equilateral triangle, then prove that|alpha-beta|=pie/3

if the three points (a,b) ,(a+lambda cos alpha, b+lambda sin alpha) , (a+lamda cos beta, b+sin beta) are the vertices of an equilateral triangle, then prove that|alpha-beta|=pie/3

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if the three points (a,b) ,(a+lambda cos alpha, b+lambda sin alpha) , (a+lamda cos beta, b+sin beta) are the vertices of an equilateral triangle, then prove that|alpha-beta|=pie/3

if the three points (a,b) ,(a+lambda cos alpha, b+lambda sin alpha) , (a+lamda cos beta, b+sin beta) are the vertices of an equilateral triangle, then prove that|alpha-beta|=pie/3

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Analytical Geometry

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