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```
if the lines joining the origin to the intersection points of the y=mx+2 and the curve x^2+y^2=1 are at right angle , then Plus 2 and the Cursed squared plus y squared

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3 years ago

```							Make the question clear.I cant get what the question is trying to ask.The last part of the question is not  clear.please use the latex to make it clear.
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3 years ago
```							If the lines joining the origin to the intersecting points of the y=mx+2 and the curve x2+y2=1 are at right angle, then(1) m2=1(2) m2=3(3) m2=7(4)  2m2=1now please give me the answer.cleared
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3 years ago
```							There is a formula you can check it in any coordinate geometry book(such as s k goyal,etc)which gives the joint equation of the pair of lines joining the origin and point of intersection of a curve and a straight line.Joint equation of the lines joining the origin to the intersecting points of the y=mx+2 and the curve x2+y2=1                                    x2+y2=((y-mx)/2)2                                       =>       x2(4-m2)+2mxy+3y2=0Since this lines are at right angles,             => 4-m2 +3=0=>m2=7so the ans is (3) m2=7I hope you have understood,and if you haven’t then please read the above mentioned topic.Please upvote my solution to encourage me.
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3 years ago
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