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if the lines joining the origin to the intersection points of the y=mx+2 and the curve x^2+y^2=1 are at right angle , then Plus 2 and the Cursed squared plus y squared
Make the question clear.I cant get what the question is trying to ask.The last part of the question is not clear.please use the latex to make it clear.
If the lines joining the origin to the intersecting points of the y=mx+2 and the curve x2+y2=1 are at right angle, then(1) m2=1(2) m2=3(3) m2=7(4) 2m2=1now please give me the answer.cleared
There is a formula you can check it in any coordinate geometry book(such as s k goyal,etc)which gives the joint equation of the pair of lines joining the origin and point of intersection of a curve and a straight line.Joint equation of the lines joining the origin to the intersecting points of the y=mx+2 and the curve x2+y2=1 x2+y2=((y-mx)/2)2 => x2(4-m2)+2mxy+3y2=0Since this lines are at right angles, => 4-m2 +3=0=>m2=7so the ans is (3) m2=7I hope you have understood,and if you haven’t then please read the above mentioned topic.Please upvote my solution to encourage me.
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