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Grade: 12th pass
        
If e and e' are eccentricity of a hyperbola and its conjucate, then state whether ee' >1 is true or false with reason? 
one year ago

Answers : (2)

Arun
23485 Points
							
Dear student
 
e^2 = 1 + b^2 /a^2 = (a^2 + b^2) / a^2
 
hence
(e’)^2 = (a^2 + b^2) / b^2
 
hence when multiplying
 
(e e’)^2 = (a^2 + b^2) ^2 / a^2 b^2
 
now use AM GM and you will find that
 
ratio os greater than one
 
one year ago
Arun
23485 Points
							
Dear student
 
You can also tell because
 
hyperbola has eccentricity greater than 1.
 
hence, whether it is conjugate hyperbola or hyperbola , eccentricity will always be 1.
 
hence 
 
e> 1 , e’ > 1
 
e e’ > 1
one year ago
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