 Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        If e and e' are eccentricity of a hyperbola and its conjucate, then state whether ee' >1 is true or false with reason? `
one year ago

```							Dear student e^2 = 1 + b^2 /a^2 = (a^2 + b^2) / a^2 hence(e’)^2 = (a^2 + b^2) / b^2 hence when multiplying (e e’)^2 = (a^2 + b^2) ^2 / a^2 b^2 now use AM GM and you will find that ratio os greater than one
```
one year ago
```							Dear student You can also tell because hyperbola has eccentricity greater than 1. hence, whether it is conjugate hyperbola or hyperbola , eccentricity will always be 1. hence  e> 1 , e’ > 1 e e’ > 1
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Analytical Geometry

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 53 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions