Soumyadeep
Last Activity: 6 Years ago
as per the given equation of circle x^2+y^2-5x-y+5=O and the given point be P(0,-2);
we know that centre of the circle is (-g,-f) from general equation of circle
now on comparing both we get centre coordinate like (5/2,1/2);
we know that radius of the circle is =√(g²+f²-c) from general equation
therefore radius of this circle is (3½/2½)
distance of the point P from centre is (5/2½)
Now For PQ to be maximum the distance should be equal = the radius + the distance of the point from centre)
PQ =(5+3½)/2½
PQ²=14+5√3