If a line cuts sides BC , CA , AB of triangle ABC at P , Q , R respectively then prove that (BP/PC)*(CQ/QA)*(AR/RB) =1

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Arun · Answer

Dear student Its product should be -1. Modulus is 1. Please check and repost this. Regards Arun (askIITians forum expert)

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If a line cuts sides BC , CA , AB of triangle ABC at P , Q , R respectively then prove that (BP/PC)(CQ/QA)(AR/RB) =1

If a line cuts sides BC , CA , AB of triangle ABC
at P , Q , R respectively then prove that
(BP/PC)(CQ/QA)(AR/RB) =1

1 Answers

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If a line cuts sides BC , CA , AB of triangle ABC at P , Q , R respectively then prove that (BP/PC)*(CQ/QA)*(AR/RB) =1

If a line cuts sides BC , CA , AB of triangle ABC at P , Q , R respectively then prove that(BP/PC)*(CQ/QA)*(AR/RB) =1

1 Answers

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Other Related Questions on Analytical Geometry

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If a line cuts sides BC , CA , AB of triangle ABC at P , Q , R respectively then prove that (BP/PC)(CQ/QA)(AR/RB) =1

If a line cuts sides BC , CA , AB of triangle ABC
at P , Q , R respectively then prove that
(BP/PC)(CQ/QA)(AR/RB) =1