If a>0 and (a^2,2a) ,(1,-2) and (2,-1) never lie on a circle, then possible value of a is a) 1b) 2c) 3d) 4
Pawan joshi , 6 Years ago
Grade 12th pass
2 Answers
Saurabh Koranglekar
Last Activity: 6 Years ago
Deepak Kumar Shringi
Last Activity: 6 Years ago
they should be collinear equation of line passing from (1,-2) and (2,-1) is y+1=-1+2/2-1(x-2) y+1=x-2 y=x-3 now if a^2,2a is also on the same line then 2a=a^2-3 a^2-2a-3=0 a=3
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