Saurabh Koranglekar
Last Activity: 6 Years ago
To determine the possible values of , we analyze the given points:
1.
2.
3.
### Step 1: Condition for Points to Lie on a Circle
For three points to lie on a circle, the determinant of the following matrix must be zero:
Since the problem states that these points **never** lie on a circle, this determinant should be **nonzero**.
### Step 2: Constructing the Determinant
Using the given points , , and , we set up the determinant:
### Step 3: Expanding the Determinant
Expanding along the first row:
#### Step 3.1: Compute the 2×2 Determinants
1. **First minor**:
2. **Second minor**:
3. **Third minor**:
### Step 4: Evaluating the Expression
Since , the expression should hold for all valid values of . We check integer values from the given options.
For :
For :
For :
For :
Since the expression is **never zero** for any of the given values, **all options are possible**. However, the question asks for a single value. The smallest valid integer satisfying the inequality is **1**.
### Final Answer:
**a = 1**