If a0 and (a^2,2a) ,(1,-2) and (2,-1) never lie on a circle, then possible value of a is a) 1 b) 2 c) 3 d) 4

Question

If a>0 and (a^2,2a) ,(1,-2) and (2,-1) never lie on a circle, then possible value of a is a) 1 b) 2 c) 3 d) 4

Saurabh Koranglekar · Answer

Deepak Kumar Shringi · Answer

they should be collinear equation of line passing from (1,-2) and (2,-1) is y+1=-1+2/2-1(x-2) y+1=x-2 y=x-3 now if a^2,2a is also on the same line then 2a=a^2-3 a^2-2a-3=0 a=3

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If a>0 and (a^2,2a) ,(1,-2) and (2,-1) never lie on a circle, then possible value of a is a) 1 b) 2 c) 3 d) 4

If a>0 and (a^2,2a) ,(1,-2) and (2,-1) never lie on a circle, then possible value of a is
a) 1
b) 2
c) 3
d) 4

2 Answers

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If a>0 and (a^2,2a) ,(1,-2) and (2,-1) never lie on a circle, then possible value of a is a) 1 b) 2 c) 3 d) 4

If a>0 and (a^2,2a) ,(1,-2) and (2,-1) never lie on a circle, then possible value of a is a) 1b) 2c) 3d) 4

2 Answers

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If a>0 and (a^2,2a) ,(1,-2) and (2,-1) never lie on a circle, then possible value of a is
a) 1
b) 2
c) 3
d) 4