If 2a+b+2c=0, then the family of lines ax+by+c=0 is concurrent at

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Vikas TU · Answer

Make ax+by+c=0 similar to 2a + b + 2c = 0 therfore multiply ax+by+c=0 by 2 .i.e. 2ax + 2by + 2c = 0 Now compare it with the coeff. of 2a+b+2c=0 we get, x = 1 y = ½ thus at this point it is concurrent.

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If 2a+b+2c=0, then the family of lines ax+by+c=0 is concurrent at

If 2a+b+2c=0, then the family of lines ax+by+c=0 is concurrent at

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