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If 2a+b+2c=0, then the family of lines ax+by+c=0 is concurrent at
Make ax+by+c=0 similar to 2a + b + 2c = 0therfore multiply ax+by+c=0 by 2 .i.e.2ax + 2by + 2c = 0Now compare it with the coeff. of 2a+b+2c=0we get,x = 1y = ½thus at this point it is concurrent.
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