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question mark

If (-2,6) is the image of the point (4,2) with respect to line L=0, then L=0
a) 6x-4y-7=0
​b) 2x+3y-5=0
c) 3x-2y+5=0
​d) 3x-2y+10=0

Gagan Deep , 10 Years ago
Grade 8
anser 3 Answers
CHANDRA KIRAN
Given,
(-2,6) is the image of the point (4,2) w.r.t. L=0.
So, L=0 is the perpendicular bisector of (-2,6) , (4,2).
Therefore, L=0 is (-2-4)x+(6-2)y = [(-2)2+62]-{42+22]/2.
So, (-6x)+4y = 10
3x-2y+5 = 0.[C].
Last Activity: 10 Years ago
CHANDRA KIRAN
If you feel that the above meathod is lengthy or complicated you can directly go from options by checking each option.
Last Activity: 10 Years ago
Anuj zanwar
For above condition the line must pass trought midpoint of two given points and there is only one which passes through the midpoint of two given points.
Last Activity: 7 Years ago
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