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Grade 8Analytical Geometry

If (-2,6) is the image of the point (4,2) with respect to line L=0, then L=0
a) 6x-4y-7=0
​b) 2x+3y-5=0
c) 3x-2y+5=0
​d) 3x-2y+10=0

Profile image of Gagan Deep
11 Years agoGrade 8
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3 Answers

Profile image of CHANDRA KIRAN
11 Years ago
Given,
(-2,6) is the image of the point (4,2) w.r.t. L=0.
So, L=0 is the perpendicular bisector of (-2,6) , (4,2).
Therefore, L=0 is (-2-4)x+(6-2)y = [(-2)2+62]-{42+22]/2.
So, (-6x)+4y = 10
3x-2y+5 = 0.[C].
Profile image of CHANDRA KIRAN
11 Years ago
If you feel that the above meathod is lengthy or complicated you can directly go from options by checking each option.
Profile image of Anuj zanwar
7 Years ago
For above condition the line must pass trought midpoint of two given points and there is only one which passes through the midpoint of two given points.

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