Analytical Geometry> I am not able to solve the following prob...

I am not able to solve the following problem#1) Prove that the normal to parabola y^2=4ax at (am^2,-2am) intersects the parabola again at an angle tan-1(m/2)What I am thinking is to solve the equation of parabola and equation of normal y=mx-am^-3 -2am simultaneously and at that point I will find the slope of tangent and will get the angle between tangent and normal. The problem is that answer is not coming.#2) For what values of a will the tangents drawn to parabola y^2=4ax from a point , not on the y-axis, will be normals to the parabola x^2=4y?I have no idea on how to solve this question\nThanks in Advance

Varun , 10 Years ago

Grade 12

1 Answers

Sher Mohammad

Last Activity: 10 Years ago

Let $P\left(a m^2,-2 a m\right) , Q\left(a n^2,-2 a n\right)$
The normal at P intersects the parabola again at Q
slope(PQ) = m and the slope of the tangent line at Q is -1/n
x = the angle that PQ makes with the horizontal
y = the angle that the tangent at Q makes with the horizontal
x-y = the angle we are looking for
With tan (x) = m and tan(y) = -1/n, use the identity
$\tan (x-y)=\frac{\tan x- \tan y}{1+\tan x *\tan y}$