Given two straight lines AB and AC whose equations

Question

Given two straight lines AB and AC whose equations are 3x + 4y = 5 and 4x – 3y = 15 respectively. Then the possible equation of line BC through (1, 2), such that ABC is isosceles, is L1 = 0 or L2 = 0, then answer the following questions
Q-If L1 ax + by + c = 0 & L2 dx + ey + f = 0 where a, b, c, d, e, f I, and a, d > 0, then c + f = (Ans is 4)

Y RAJYALAKSHMI · Accepted Answer

Equation of the line BC passing through (1,2) with slope ‘m’ is (y-2) = m(x-2)Since ABC is isosceles, angle B = angle C.using Cos(theta) formula for finding angle between the lines AB,BC & AC,BC, and equating them we get m = 1/7 or -7. Substituting thes values in equation, we get x-7y + 13 = 0 & 7x + y – 9 = 0. So c+f = 13-9=4 (ANS)

Analytical Geometry> Given two straight lines AB and AC whose ...

Aditya Vishnu , 11 Years ago

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Analytical Geometry> Given two straight lines AB and AC whose ...

Aditya Vishnu , 11 Years ago

Y RAJYALAKSHMI

LIVE ONLINE CLASSES

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