Given the base of a triangle and the ratio of the lengths of other two unequal sides prove that the vertex lies on a fixed circle

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Saurabh Koranglekar · Answer

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Given the base of a triangle and the ratio of the lengths of other two unequal sides prove that the vertex lies on a fixed circle

Given the base of a triangle and the ratio of the lengths of other two unequal sides prove that the vertex lies on a fixed circle

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Given the base of a triangle and the ratio of the lengths of other two unequal sides prove that the vertex lies on a fixed circle

Given the base of a triangle and the ratio of the lengths of other two unequal sides prove that the vertex lies on a fixed circle

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Analytical Geometry

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Answer and earn gift vouchers

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