Find the the equation of a circle which passes through the intersection points of the the lines x - y - 3 = 0 and 3x - 10y + 5 = 0 and centered at ( 2, - 2 ).

Question

Piyush Kumar Behera · Answer

IS (5,2) . intersection points of the the lines x - y - 3 = 0 and 3x - 10y + 5 = 0 RADIUS = DISTANC BETWEEN THE POINTS ( 2,- 2) AND (5,2) = =5 EQUATION OF THE CIRCLE=(X-2) 2 +(Y+2) 2 =25

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Find the the equation of a circle which passes through the intersection points of the the lines x - y - 3 = 0 and 3x - 10y + 5 = 0 and centered at ( 2, - 2 ).

Find the the equation of a circle which passes through the intersection points of the the lines x - y - 3 = 0 and 3x - 10y + 5 = 0 and centered at ( 2, - 2 ).

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Find the the equation of a circle which passes through the intersection points of the the lines x - y - 3 = 0 and 3x - 10y + 5 = 0 and centered at ( 2, - 2 ).

Find the the equation of a circle which passes through the intersection points of the the lines x - y - 3 = 0 and 3x - 10y + 5 = 0 and centered at ( 2, - 2 ).

1 Answers

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Other Related Questions on Analytical Geometry

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