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        Find the the equation of a circle which passes through the intersection points of the the lines x - y - 3 = 0 and 3x - 10y + 5 = 0 and centered at ( 2, - 2 ).
3 years ago

Piyush Kumar Behera
433 Points
							 IS (5,2) .intersection points of the the lines x - y - 3 = 0 and 3x - 10y + 5 = 0 RADIUS = DISTANC BETWEEN THE POINTS (2,- 2) AND  (5,2)            =$\sqrt{9+16}$ =5EQUATION OF THE CIRCLE=(X-2)2+(Y+2)2=25

3 years ago
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### Course Features

• 53 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions