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# Find the the equation of a circle which passes through the intersection points of the the lines x - y - 3 = 0 and 3x - 10y + 5 = 0 and centered at ( 2, - 2 ).

Piyush Kumar Behera
436 Points
5 years ago
IS (5,2) .intersection points of the the lines x - y - 3 = 0 and 3x - 10y + 5 = 0
RADIUS = DISTANC BETWEEN THE POINTS (2,- 2) AND  (5,2)
=$\sqrt{9+16}$ =5
EQUATION OF THE CIRCLE=(X-2)2+(Y+2)2=25