Find the the equation of a circle which passes through the intersection points of the the lines x - y - 3 = 0 and 3x - 10y + 5 = 0 and centered at ( 2, - 2 ).
T Jahnavi , 9 Years ago
Grade 11
1 Answers
Piyush Kumar Behera
IS (5,2) .intersection points of the the lines x - y - 3 = 0 and 3x - 10y + 5 = 0
RADIUS = DISTANC BETWEEN THE POINTS (2,- 2) AND (5,2)
= =5
EQUATION OF THE CIRCLE=(X-2)2+(Y+2)2=25
Last Activity: 9 Years ago
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.