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Grade: 10
        Find the sum to n terms of the series 1•2•3+2•4•6+3•6•9+.........
3 years ago

Answers : (1)

Ojas Raundale
16 Points
							1.2.3 + 2.4.6 + 3.6.9 +.....+ n.2n.3n= 1.2.3[ 1^3 + 2^3 +3^3 +4^3+ .... + n^3]=1.2.3[ (n)(n+1)/2]^2=3/2[(n)(n+1)]^2
						
3 years ago
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