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Find the max. distance between (3sin@,0,0) and (4cos@,0,0).

Find the max. distance between (3sin@,0,0) and (4cos@,0,0).

Grade:12

1 Answers

Arun
25763 Points
3 years ago
Dear student
 
Distance between those two points = sqrt[(3 sin@- 4 cos@)² + 0]
Now maximum value of 3 sin@ - 4 coc@ = 5
Hence
Distance = sqrt[(5)²] = 5 units

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