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Find the inerse point of (-2,3) with respect to the circle x^2+y^2-4x-6y+9=0

Find the inerse point of (-2,3) with respect to the circle x^2+y^2-4x-6y+9=0

Grade:12

1 Answers

Sri ganesh
15 Points
8 months ago
Inverse point is the foot of perpendicular of the given point on its polar.
Polar ;  X=1
 
So, Inverse point is (1,3)

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