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Find the inerse point of (-2,3) with respect to the circle x^2+y^2-4x-6y+9=0 Find the inerse point of (-2,3) with respect to the circle x^2+y^2-4x-6y+9=0
Inverse point is the foot of perpendicular of the given point on its polar.Polar ; X=1 So, Inverse point is (1,3)
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