Find the focus and the directrix of the parabola y2 = 2p(x – 4p) and give the length of the latus rectum
Find the focus and the directrix of the parabola y2 = 2p(x – 4p) and give the length of the latus rectum
Samuel William , 6 Years ago
Grade 12
Analytical Geometry> Find the focus and the directrix of the p...
4 Answers
Vikas TU
Dear student
Please specify what is p here ? Is it a constant or some variable.
You can also attach an image
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Good luck
Approved Last Activity: 6 Years ago
Aditya Gupta
vikas’ ans is the crappiest ans here. the correct ans is as follows and the ques is perfectly fine.
let p= 2a.
so, eqn is y2 = 4a(x – 8a)= 4aX, where X= x – 8a
now obviously focus, directrix and latus rectum of y^2= 4aX are (a, 0), X= – a and 4a.
so, in our original coordinate system, focus is (8a + a, 0), directrix is x – 8a= – a or x= 7a and latus rectum= 4a (as it is a length).
so, focus: (9p/2, 0)
directrix: 2x= 7p
LR= 2p
kindly approve :)
Approved Last Activity: 6 Years ago
Samuel William
@Viska Tu
In my country, we use p instead of a. So the question is to find the focus, directrix and latus rectum of the parabola;
y2 = 2a (x – 4a)
Samuel William
@Aditya
Thanks for your answer. But how do I solve the problem if the parabola was; y2 = 2a (x – 4a).
thank you.
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