MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        
Find the focus and the directrix of the parabola y2 = 2p(x – 4p) and give the length of the latus rectum
9 months ago

Answers : (4)

Vikas TU
11680 Points
							
Dear student 
Please specify what is p here ? Is it a constant or some variable. 
You can also attach an image 
We will help you
Good luck
9 months ago
Aditya Gupta
2016 Points
							
vikas’ ans is the crappiest ans here. the correct ans is as follows and the ques is perfectly fine.
let p= 2a.
so, eqn is y2 = 4a(x – 8a)= 4aX, where X= x – 8a
now obviously focus, directrix and latus rectum of y^2= 4aX are (a, 0), X= – a and 4a.
so, in our original coordinate system, focus is (8a + a, 0), directrix is x – 8a= – a or x= 7a and latus rectum= 4a (as it is a length).
so, focus: (9p/2, 0)
directrix: 2x= 7p
LR= 2p
kindly approve :)
9 months ago
Samuel William
25 Points
							
@Viska Tu
In my country, we use p instead of a. So the question is to find the focus, directrix and latus rectum of the parabola;
y2 = 2a (x – 4a)
 
9 months ago
Samuel William
25 Points
							
@Aditya
Thanks for your answer. But how do I solve the problem if the parabola was; y= 2a (x – 4a).
thank you.
9 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 53 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details