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Grade: 12
        
Find the focus and the directrix of the parabola y2 = 2p(x – 4p) and give the length of the latus rectum
one month ago

Answers : (4)

Vikas TU
9163 Points
							
Dear student 
Please specify what is p here ? Is it a constant or some variable. 
You can also attach an image 
We will help you
Good luck
one month ago
Aditya Gupta
1690 Points
							
vikas’ ans is the crappiest ans here. the correct ans is as follows and the ques is perfectly fine.
let p= 2a.
so, eqn is y2 = 4a(x – 8a)= 4aX, where X= x – 8a
now obviously focus, directrix and latus rectum of y^2= 4aX are (a, 0), X= – a and 4a.
so, in our original coordinate system, focus is (8a + a, 0), directrix is x – 8a= – a or x= 7a and latus rectum= 4a (as it is a length).
so, focus: (9p/2, 0)
directrix: 2x= 7p
LR= 2p
kindly approve :)
one month ago
Samuel William
25 Points
							
@Viska Tu
In my country, we use p instead of a. So the question is to find the focus, directrix and latus rectum of the parabola;
y2 = 2a (x – 4a)
 
one month ago
Samuel William
25 Points
							
@Aditya
Thanks for your answer. But how do I solve the problem if the parabola was; y= 2a (x – 4a).
thank you.
one month ago
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