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Find the equation to the circle which: touches the axes of coordinates and also the line x/a+y/b=1 the centre being in the positive quarant.

Find the equation to the circle which: touches the axes of coordinates and also the line x/a+y/b=1 the centre being in the positive quarant.

Grade:11

1 Answers

Nishant Vora IIT Patna
askIITians Faculty 2467 Points
7 years ago
Let (h,h) be the center as its center is equidistant from the axes. So rad = h

Now perpendicular distance from center to linex/a+y/b=1 equals radius

h/a+h/b-1 / root(1/a^2 + 1/b^2 ) = h

From here find h

Hence we get the eqn of circle as (x-h)^2 + (y-h)^2 = h^2

thanks

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