Find the equation of the line passing through the point (3,2,-8) and is perpendicular to the plane -3x+y+2z-2=0. Book answer:(x-3)/3=(y+2)/1=(z+8)/2

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Arun · Answer

Dear student Answer should be (x- 3)/ – 3 = (y- 2) /1 = (z+8)/2 Answer , which you have written above is incorrect. Please check and let me know

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Find the equation of the line passing through the point (3,2,-8) and is perpendicular to the plane -3x+y+2z-2=0. Book answer:(x-3)/3=(y+2)/1=(z+8)/2

Find the equation of the line passing through the point (3,2,-8) and is perpendicular to the plane -3x+y+2z-2=0.
Book answer:(x-3)/3=(y+2)/1=(z+8)/2

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Find the equation of the line passing through the point (3,2,-8) and is perpendicular to the plane -3x+y+2z-2=0. Book answer:(x-3)/3=(y+2)/1=(z+8)/2

Find the equation of the line passing through the point (3,2,-8) and is perpendicular to the plane -3x+y+2z-2=0. Book answer:(x-3)/3=(y+2)/1=(z+8)/2

1 Answers

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Find the equation of the line passing through the point (3,2,-8) and is perpendicular to the plane -3x+y+2z-2=0.
Book answer:(x-3)/3=(y+2)/1=(z+8)/2