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`        find the equation of the circles which touches the line 3x+y+3=0 at (-3,6) and tangent to x+3y-7=0. I AM REQUESTING ARUN TO PLEASE SOLVE THE WHOLE SUM AND NOT SIMPLY GIVE THE STEPS....`
one year ago

Arun
23491 Points
```							Dear student By family of circles Eqn of circle-(x +3)² + (y -6)² + s(3x+y+3) = 0 x² + y² + x(6 +3s) + y (s -12) + (45 +3s) = 0 Also this is a tangent to x + 3y -7 = 0 Hence Now perpendicular length = radius thus you get value of s.
```
one year ago
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### Course Features

• 53 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions