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Find the equation of the circles passing through (-4,3) and touching the lines x+y=2 and x-y=2.

Find the equation of the circles passing through (-4,3) and touching the lines x+y=2 and x-y=2.

Grade:12th pass

2 Answers

dattatreyamunshi
16 Points
5 years ago
(x-6)+ (y-6)2 = 26
dattatreyamunshi
16 Points
5 years ago
Expalnation
The two lines are perpendicular to each other and are also tangents of the circle. So the intersection point of these two lines lies on the director circle whose radius is 20.5R so assuming the centre of the circle to be h,k and using the general equation of the circle and putting co-ordinates (-4,3) in the equation and putting co-ordinates (2,0) in the director circle's general equation and solving it terms of h,k to get the equation of the circle i.e.
                                                                                     (x-6)+ (y-6)2 = 26
 

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