Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
Find the equation of straight line passing through the intersection of the lines 5x-2y-12=0 and 4x-7y-15=0 and parallel to the line 3x-2y+5=0 Find the equation of straight line passing through the intersection of the lines 5x-2y-12=0 and 4x-7y-15=0 and parallel to the line 3x-2y+5=0
Dear StudentThe intersection point of two lines can be calculated by solving the linear equation of both lines .By solving given equations, we will getx=2y= –1The line parallel to line ax+by+c=0 is given by ax+by+d=0so line equation will be 3x –2y + d=0since line passes through (2,-1)3 x 2 –2 x (-1) +d=0d= –8so , The equation of line is 3x-2y-8=0Thanks
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -