SREEKANTH
Last Activity: 8 Years ago
the line passing through the point=(4,5)
the line equally inclined to the lines 3x=4y+7,5y=12x+6 means the angle between the required line and the two lines is equalassume the slop of the required equation is m1
the slope of the equation 3x=4y+7=>y=(3x)/4-7/4 so the slope of the equation is ¾
the slope of the equation 5y=12x+6=>y=(12x)/5+6/5 so the slope of the equation is 12/5
when slope of the two equations are formula for finding the angle between them is
a=tan^-1(m1-m2)/1+m1m2=tan^-1(m1-m2)/1+m1m2
=tan^-1(m1-3/4)/1+3m1/4=tan^-1(m1-12/5)1+12m1/5)
=>(4m1-3)/(4+3m1)=(5m1-12)/(5+12m1)
=>(20m1+48m1^2-15-36m1=20m1+15m1^2-48-36m1)
=>m1^2=1
=>m1=+1 or -1
so the two equations incline the given ttwo equations equally
those are passing throught he point (4,5) and having the slope 1 and -1
those arey-x+1=0 and y+x-9=0
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