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equations of lines which passes through the points of intersection of the lines 4x-3y-1=0and 2x-5y+3=0and are equally inclined to the axes are:y(+or-)x=0y-1=(+or-)1(x-1)x-1=(+or-)2(y-1)none of these

nikhita , 8 Years ago
Grade 11
anser 1 Answers
Ajay

Last Activity: 8 Years ago

The Point of intersection is (1, 1)
The equation of line passing through this point is
y-1 = m(x-1) where m is slope
or y-mx + m-1 = 0.
Since line makes equal with both axes this is possible line makes 45 or 135 degree with x axis.
The slopes thus can be tan45 or tan 135 or m can take values 1  or -1
Putting m = 1 and -1 in equation we wll get two equations as follows
y = x and
y+x-2=0 as equations of lines

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