equation of the pair of lines passing through the orgin whose sum and product of slopes are A.M. and G.M. of 4 and 16 is ?

Question

Harsh Patodia · Answer

AM of 4,16 is=10 GM of 4,16 is =8 m 1 +m 2 =10 m 1 m 2 =8 so equation will be (y-m 1 x)(y-m 2 x)=0 y 2 -(m 1 +m 2 )xy+m 1 m 2 x 2 =0 y 2 -10xy+8x 2 =0

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equation of the pair of lines passing through the orgin whose sum and product of slopes are A.M. and G.M. of 4 and 16 is ?

equation of the pair of lines passing through the orgin whose sum and product of slopes are A.M. and G.M. of 4 and 16 is ?

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equation of the pair of lines passing through the orgin whose sum and product of slopes are A.M. and G.M. of 4 and 16 is ?

equation of the pair of lines passing through the orgin whose sum and product of slopes are A.M. and G.M. of 4 and 16 is ?

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