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angles between the lines represented by 6x^2+6y^2+13xy+8x+7y+2=0

Shubham Pathak , 8 Years ago
Grade 12
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

 The angle between pair of straight lines  represented by ax^2 + 2hxy + by^2 + 2gx + 2fy +c =0 is given by --------1
tanthetha= | (2( h^2 – ab) ^ ½ ) / (a+b) |
comparing the equation given in question with 1
a=6 ; b= 6 ; h = 13/2 ; g=4; f= 7/2 ; c= 2;
tanthetha = | (2( 13/2 ^2 – 6 . 6 ) ^ ½ ) / (6 + 6) |
tanthetha = | (2( 6.25 ) ^ ½ ) / 12 |
tanthetha=| 5/12 |
Hence thetha = tan-1 5/12

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