ABC is an equilateral triangle. Let P be any point inside it such that PA=3 PB=5 PC=4 Then find area of he triangle ABC?

Question

Aditya Gupta · Answer

you will have to rotate the triangle 60 deg about one of its vertices and then note a 60 deg angle. apply cosine rule and finally obtain a^2= 25+12root3 hence area= root3 * a^2/4 actually this is a tricky question and wont be asked in any exam. the solution to this is easily available on google search as well. it has a long history behind it and is also a ‘coffin’ problem asked in the early 90s to discriminate against the black kids.

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ABC is an equilateral triangle. Let P be any point inside it such that PA=3 PB=5 PC=4 Then find area of he triangle ABC?

ABC is an equilateral triangle. Let P be any point inside it such that PA=3 PB=5 PC=4 Then find area of he triangle ABC?

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ABC is an equilateral triangle. Let P be any point inside it such that PA=3 PB=5 PC=4 Then find area of he triangle ABC?

ABC is an equilateral triangle. Let P be any point inside it such that PA=3 PB=5 PC=4 Then find area of he triangle ABC?

1 Answers

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