# A tangent to the hyperbola 3x^2 – 4y^2 = 12 makes equal intercept on the axes. Then the area of the triangle formed by the tangent with coordinate axes is ????a)2b)1/4c)4d)1/2please give a complete solution for the question

Arun
25757 Points
3 years ago
x²/ 4 - y²/3 = 1 ⇒a² = 4, b² = 3
x/k + y/k = 1 or x + y = k or y = - x + k
⇒  m = -1 and c = k
Now k² = a² m² - b²
= 4(-1)² - 3
= 4-3
= 1
⇒ k = + - 1
So the equation of the tangents are: x + y = + - or x + y + - = 0
it can also be taken as  x - y = k
Then k  = + - 1 and  x - y = + - 1
or x - y +-1 = 0

hence area = ½ * 1 * 1 = ½

ishu
13 Points
one year ago
72 +8hhhhh
bbbbbh
jjjj​   ∫87 $\lim_{h\rightarrow 0}$ idk i’m writing all
this for fun
$\lim_{h\rightarrow \infty }$ x+ y/8
87+98=67
hence ans is 89
= 4(-1)² - 3
= 4-3
= 1
⇒ k = + - 1