siddharth gupta
Last Activity: 10 Years ago
intercept form:
x/a+y/2a=1
on solving 2x+y=2a.......(1.)
normal form:
xcos(m)+ysin(m)=1.........(2.)
now adjust eqn (1.) to obtain eqn(2)
i.e make the sum of squares of coefficients of x and y in eq.(1) equal to 1
for that divide the eqn. on both sides by ((2)2+(1)2)1/2
the resultant eqn. is (2/(5)1/2)x+(1/(5)1/2)y=2/(5)1/2a.....(3.)
on comparing with eqn(2) a=(5)1/2/2
put the value of a in eqn 2
RESULT IS:2x+y=(5)1/2
WITH REGARDS
SIDDHARTH GUPTA
no
