Ajay
Last Activity: 8 Years ago
Let ABCD be the square with side AB on tangent .
CD will be a chord for circle.
Let M be the mid point of CD, N be mid point of AB and O be the center of the circle, then OM will be be perpendicular to CD.
Side of the square = radius of circle + OM = 5+OM.
SInce CD is also sdie of square M being mid point MD = (5+OM)/2
IN traingle OMD
OM2+MD2=OD2
OM2+ 1/4(5+OM)2 = 25
solving for OM , OM = 3.
Hence side of square = 5+3 = 8cm and area = 64cm