Vikas TU
Last Activity: 8 Years ago
Assume hypertenuse lying on coordinate axes as having points
(a,0) and (0,b).
The other coordinate of right angle triangle as issoceles will be then (a,b)
And let centroifd of the triangle be (h,k)
Now interpret the relations between these parameters and solve.
h = 2a/3 or a = 3h/2--------------------(1)
k = 2b/3 or b = 3k/2--------------(2)
Now from Pyhogorus
Hypertenuse^2 = a^2 + b^2 = 484 (given.)---------------------(3)
from eqns. (!) and (2)
put in (3)
h^2 + k^2 = 484*4/9
or
x^2 + y^2 = 484*4/9
hence locus is circle.