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A rectangle ABCD is inscribed in the circle x^2 + y^2 + 3x + 12y + 2 = 0. If the coordinates of A and B are respectively (3, – 2) and (–2, 0) then the coordinates of the mid-point of CD are
Dear studentangle DAB is 90so BD is the diametersimilarly, AC is the diameterwhich can be found thus C and DRegards
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