A ray of light is sent along the line x-6y=8,after refracting across the line x+y=1,it enters the opposite side after turning by 15°away from line x+y=1.Find the equation of line along which refracted ray travels.

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ANIKET RAJ · Answer

√3y+x=1....................................................................................................................................................................................................................................................................

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A ray of light is sent along the line x-6y=8,after refracting across the line x+y=1,it enters the opposite side after turning by 15°away from line x+y=1.Find the equation of line along which refracted ray travels.

A ray of light is sent along the line x-6y=8,after refracting across the line x+y=1,it enters the opposite side after turning by 15°away from line x+y=1.Find the equation of line along which refracted ray travels.

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A ray of light is sent along the line x-6y=8,after refracting across the line x+y=1,it enters the opposite side after turning by 15°away from line x+y=1.Find the equation of line along which refracted ray travels.

A ray of light is sent along the line x-6y=8,after refracting across the line x+y=1,it enters the opposite side after turning by 15°away from line x+y=1.Find the equation of line along which refracted ray travels.

1 Answers

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