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Grade: 11
        
A question from parabola.
Please answer this question.
3 months ago

Answers : (1)

Shivank Shekhar
14 Points
							
For simplicity assume that that one of the normals drawn at the vertex of the parabola Y^2=4ax and other two are drawn at the points that is P t1 and q t2.
Now it means that normal will meet on the x axis.
A= 2a+ a(t1^2+t2^2+t1t2), -at1t2(t1+t2)
Since Y co-ordinate of A is zero therefore T1 is equal to T2
PS=a
QS=SR=a+at^2
SA= a+at^2
Therefore PS.QS.SR=aSA^2.
3 months ago
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