Ajay Verma
Last Activity: 11 Years ago
ans:
total displacement in X direction :
step-1 : 1 unit right (+ve X direction)
step-3 : 1/22unit left (-ve X deirction)
step-5: 1/24unit right ( +ve X direction)
step-7 : 1/26unit ( -ve X direction)
and so on..
so total displacement in X direction: (X-coordinate)
X= 1 - 1/22+ 1/24_1/26+ 1/28 - ........................................ up to infinity
its an G.P. so sum of it :
X = 1/ {1+ 1/22} sum of G.P = a/ (1-r)
1st term = 1 and C.R. = -1/22
X = 4/5
similarly
total displacement in Y direction :
step-2 : 1/2 unit up (+ve Y direction)
step-4 : 1/23unit down (-ve Y deirction)
step-6: 1/25unit up ( +ve Y direction)
step-7 : 1/27unit ( -ve Y direction)
and so on..
so total displacement in Y direction: (Y-coordinate):
Y= 1/2 - 1/23+ 1/25 - 1/27.................................................. up to infinity
its a g.p.
so sum : Y = 1/2*{1 +1/22} 1st term = 1/2 and C.R. = -1/22
Y = 2/5
so coordinates : (4/5 , 2/5)
Thanks and Regards,
Ajay verma,
askIITians faculty,
IIT HYDERABAD
