A field is in the shape of a trapezium whose parallel sides are 25m and 10m the non-parallel Sides are 14m and 13m,Find the area of field

Question

Rajat · Answer

Let ABCD be the trapezium. And AB= 10 CD=25 BC=13 AD=14. Let AE and BF be perpendicular on CD, so AE=BF Triangle ADE, BCF are right angled. AB=EF=10. Let CF = X so, DE = 15-X By Pythagoras Theorem 14 2 +(X-15) 2 = 13 2 +(X) 2 so X comes out to be 252/30= 8.4 So, AE= BF = √(13 2 -8.4 2 ) = 9.92 So area of trapezium = 1/2(10+25)(9.92)= 173.6

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A field is in the shape of a trapezium whose parallel sides are 25m and 10m the non-parallel Sides are 14m and 13m,Find the area of field

A field is in the shape of a trapezium whose parallel sides are 25m and 10m the non-parallel Sides are 14m and 13m,Find the area of field

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