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A field is in the shape of a trapezium whose parallel sides are 25m and 10m the non-parallel Sides are 14m and 13m,Find the area of field

Vignesh , 6 Years ago
Grade 9
anser 1 Answers
Rajat

Last Activity: 6 Years ago

Let ABCD be the trapezium. And AB= 10 CD=25 BC=13 AD=14. 
Let AE and BF be perpendicular on CD, so AE=BF
Triangle ADE, BCF are right angled.
AB=EF=10. Let CF = X so, DE = 15-X 
By Pythagoras Theorem 142+(X-15)2= 132+(X)2
so X comes out to be 252/30= 8.4 
So, AE= BF = √(132-8.42) = 9.92
So area of trapezium = 1/2(10+25)(9.92)= 173.6
 

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