A circle passes through (2,1) and x+2y=1 is tangent to it at (3,-1). Find its equation
Rajat Srivastava , 8 Years ago
Grade 11
Analytical Geometry> A circle passes through (2,1) and x+2y=1 ...
1 AnswersVikas TU
Last Activity: 8 Years ago
find the perpendicular distance from cenetr of circle to the given tangent.
m = |x1 + 2y1 – 1|/|root(x1^2 + y1^2)| and equate it to
root((x1-3)^2 + (y1+1)^2) = m {from distance formulae}
where x1 and y1 is the center of the circle.
Now we need one more eqn. that would come from (2,1)
Apply distance formulae b/w (2,1) and (x1,y1) also and sam equate it with m and solve for x1 and y1.
thus U get the center of the circle + raddi by sistance formulae.
u can calute its eqn.
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