MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
4 5 6 7 ............?....?.............................................................
10 months ago

Answers : (1)

sahil
142 Points
							There are 4 question so i will solve them one by one first we proceed with 4-)There is a well know theorem in hyperbola that any tangent to hyperbola makes constant area with two asymptotes and that area  is equal to AB.Now area is given a^2tan which is equal to ab .Now b=a(e^2-1)^1/2 so ab can be written a^2(e^2-1)^1/2.Now compare a^2tan=a^2(e^2-1)^1/2 or tan=(e^2-1)^1/2 or tan^2=e^2-1 or tan^2+1=e^2 finally e=sec.Hence answer is ecentricity=sec(lamda)
						
10 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 53 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 148 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details