1.] the equation of a locus is x 2 +y 2 -4x+6y-3=0.Show that the equation becomes x 2 +y 2 =16 if the origin is shifted.

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Badiuddin askIITians.ismu Expert · Answer

Dear Ashwathy x 2 +y 2 -4x+6y-3=0 (x-2) 2 + (y+3) 2 =16 this is a equation of circle having center ( 2,-3) so now shift the origin at (2,-3) x' =x+2 y'=y-3 so equation become x 2 +y 2 =16 Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards, Askiitians Experts Badiuddin

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1.] the equation of a locus is x 2 +y 2 -4x+6y-3=0.Show that the equation becomes x 2 +y 2 =16 if the origin is shifted.

1.] the equation of a locus is x²+y²-4x+6y-3=0.Show that the equation becomes x²+y²=16 if the origin is shifted.

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1.] the equation of a locus is x 2 +y 2 -4x+6y-3=0.Show that the equation becomes x 2 +y 2 =16 if the origin is shifted.

1.] the equation of a locus is x2+y2-4x+6y-3=0.Show that the equation becomes x2+y2=16 if the origin is shifted.

1 Answers

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1.] the equation of a locus is x²+y²-4x+6y-3=0.Show that the equation becomes x²+y²=16 if the origin is shifted.