1.] the equation of a locus is x2+y2-4x+6y-3=0.Show that the equation becomes x2+y2=16 if the origin is shifted.

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Grade Upto college levelAnalytical Geometry

1.] the equation of a locus is x²+y²-4x+6y-3=0.Show that the equation becomes x²+y²=16 if the origin is shifted.

Ashwathy Menon

16 Years agoGrade Upto college level

1 Answer

Badiuddin askIITians.ismu Expert

16 Years ago

Dear Ashwathy

x²+y²-4x+6y-3=0

(x-2)²+ (y+3)² =16

this is a equation of circle having center ( 2,-3)

so now shift the origin at (2,-3)

x' =x+2

y'=y-3

so equation become x²+y² =16

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