Kushagra Madhukar
Last Activity: 4 Years ago
Dear student,
Please find the solution to the question.
The area of triangle with vertices: (x1, y1), (x2, y2), (x3, y3) is
A = ½ | x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) |
Using this we get the area of ΔABC = 49/2
similarly, we find the area of triangle DBC
ΔDBC =7|2x-1|
now given ΔDBC/ΔABC = 1/2
7|2x – 1|/(49/2) = 1/2
2 |2x – 1|/7 =1/2
|2x – 1| = 7/4
2x – 1 = ±7/4
Hence, x = 11/8 or –3/8
Thanks and regards,
Kushagra