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LET /\ABC BE ISOSCELES WITH AB=AC,P BE ITS INCENTRE ,GIVEN BC=AB+AP,FIND / BAC
Dear MITHRESH
In triangle APE
r =AP sinx
In triangle ADB
BD =BC/2 = ABsinx
BC =2AB sinx
and cosx =(AP +r)/AB
= AP(1+sinx)/AB
AP = AB cosx/(1+sinx)
given BC =AP +AB
2AB sinx = AB cosx/(1+sinx) +AB
simplyfy
sinx -cosx =1- 2sin2x
sinx -cosx = cos2x
square
1- sin2x = cos22x
sin2x= sin22x
sin2x=1
2x=90
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