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if the pairof the lines ax2+2axy+2bxy+by2=0 lie along the diameters of a circle and divide it into four sectors such that area of one of the sectors is thrice that of the other then which of the following is true?? 3a2-2ab+3b2=0 3a2-10ab+3b2=0 3a2+2ab+3b2=0 3a2+10ab+3b2=0

if the pairof the lines ax2+2axy+2bxy+by2=0 lie along the diameters of a circle and divide it into four sectors such that area of one of the sectors  is thrice that of the other then which of the following is true??


3a2-2ab+3b2=0


3a2-10ab+3b2=0


3a2+2ab+3b2=0


3a2+10ab+3b2=0

Grade:11

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear shivanshi

ax2+2axy+2bxy+by2=0 lie along the diameters of a circle

these two lines are diameter of circle,only possible if the center of circle is at origin.



6971-2191_7662_untitled.JPG

one part is 3 times the other then angel of onle part must be thrice the other

 so angel between two lines must be 45

tan45 = 2√(h2-ab)/(a+b)

1 = 2√((a+b)2-ab)/(a+b)

(a+b)2 = 4[((a+b)2-ab)]

3a2+2ab+3b2=0


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Badiuddin

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