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if the pairof the lines ax2+2axy+2bxy+by2=0 lie along the diameters of a circle and divide it into four sectors such that area of one of the sectors is thrice that of the other then which of the following is true??
3a2-2ab+3b2=0
3a2-10ab+3b2=0
3a2+2ab+3b2=0
3a2+10ab+3b2=0
Dear shivanshi
ax2+2axy+2bxy+by2=0 lie along the diameters of a circle
these two lines are diameter of circle,only possible if the center of circle is at origin.
one part is 3 times the other then angel of onle part must be thrice the other
so angel between two lines must be 45
tan45 = 2√(h2-ab)/(a+b)
1 = 2√((a+b)2-ab)/(a+b)
(a+b)2 = 4[((a+b)2-ab)]
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