if the pairof the lines ax2+2axy+2bxy+by2=0 lie along the diameters of a circle and divide it into four sectors such that area of one of the sectors is thrice that of the other then which of the following is true??

3a2-2ab+3b2=0

3a2-10ab+3b2=0

3a2+2ab+3b2=0

3a2+10ab+3b2=0

Dear shivanshi

ax²+2axy+2bxy+by²=0 lie along the diameters of a circle

these two lines are diameter of circle,only possible if the center of circle is at origin.

one part is 3 times the other then angel of onle part must be thrice the other

 so angel between two lines must be 45

tan45 = 2√(h²-ab)/(a+b)

1 = 2√((a+b)²-ab)/(a+b)

(a+b)² = 4[((a+b)²-ab)]

3a²+2ab+3b²=0

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