The foci of hyperbola xy=(a^2+b^2)/4 are given by

a.x=y=+ (a^2+b^2)/4a

b.x=y=+ (a^2+b^2)/4b

c.x=y=+ (a^2+b^2)/2a

d.none

Question

The foci of hyperbola xy=(a^2+b^2)/4 are given by a.x=y= + (a^2+b^2)/4a b.x=y= + (a^2+b^2)/4b c.x=y= + (a^2+b^2)/2a d.none

Saurabh Koranglekar · Answer

Dear student The solution is concept based which can be found on the link below https://www.askiitians.com/iit-jee-hyperbola/rectangular-hyperbola/ Regards

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The foci of hyperbola xy=(a^2+b^2)/4 are given by a.x=y= + (a^2+b^2)/4a b.x=y= + (a^2+b^2)/4b c.x=y= + (a^2+b^2)/2a d.none

The foci of hyperbola xy=(a^2+b^2)/4 are given by

a.x=y=+ (a^2+b^2)/4a

b.x=y=+ (a^2+b^2)/4b

c.x=y=+ (a^2+b^2)/2a

d.none

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The foci of hyperbola xy=(a^2+b^2)/4 are given by a.x=y= + (a^2+b^2)/4a b.x=y= + (a^2+b^2)/4b c.x=y= + (a^2+b^2)/2a d.none

The foci of hyperbola xy=(a^2+b^2)/4 are given by a.x=y=+ (a^2+b^2)/4a b.x=y=+ (a^2+b^2)/4b c.x=y=+ (a^2+b^2)/2a d.none

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The foci of hyperbola xy=(a^2+b^2)/4 are given by

a.x=y=+ (a^2+b^2)/4a

b.x=y=+ (a^2+b^2)/4b

c.x=y=+ (a^2+b^2)/2a

d.none