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The foci of hyperbola xy=(a^2+b^2)/4 are given by a.x=y= + (a^2+b^2)/4a b.x=y= + (a^2+b^2)/4b c.x=y= + (a^2+b^2)/2a d.none

The foci of hyperbola xy=(a^2+b^2)/4 are given by


a.x=y=(a^2+b^2)/4a


b.x=y=(a^2+b^2)/4b


c.x=y=(a^2+b^2)/2a


d.none

Grade:12

1 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
Dear student

The solution is concept based which can be found on the link below

https://www.askiitians.com/iit-jee-hyperbola/rectangular-hyperbola/

Regards

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