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The foci of hyperbola xy=(a^2+b^2)/4 are given bya.x=y=+(a^2+b^2)/4ab.x=y=+(a^2+b^2)/4bc.x=y=+(a^2+b^2)/2ad.none

Vaibhav Mathur , 15 Years ago
Grade 12
anser 1 Answers
Saurabh Koranglekar

Last Activity: 4 Years ago

Dear student

The solution is concept based which can be found on the link below

https://www.askiitians.com/iit-jee-hyperbola/rectangular-hyperbola/

Regards

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