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slope of given line is 2, eqn is y = 2x + 3/2
its perpendicular eqn is of form , y = -1/2x + c where is c in intercept to be found ,as
this eqn is tangent , its perpendicular distance from center is equal to radius of 5 units
5 = c / (5/4)1/2
so , c = 5/2*(5)1/2
so eqn of tangent is : 2y + x - 5*(5)1/2 =0
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regards
Ramesh
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