parabola

Question

Normal 0 false false false EN-US X-NONE X-NONE Let V be the vertex and L be the latusrectum of the parabola x2 = 2y + 4x &ndash; 4. Then the equation of the parabola whose vertex is at V, latusrectum is L/2 and axis is perpendicular to the axis of the given parabola. (a) y2 = x &ndash; 2 (b) y2 = x &ndash; 4 (c) y2 = 2 &ndash; x (d) y2 = 4 &ndash; x

Amit Saxena · Accepted Answer

(AC) Sol. x2 &ndash; 4x = 2y &ndash; 4 x2 &ndash; 4x + 4 = 2y &ndash; 4 + 4 (x &ndash; 2)2 = 2y vertex of parabola (2, 0) and length of latusrectum = 2 length of latusrectum of the required parabola = 1 \ equation of the required parabola is (y &ndash; 0)2 = + 1(x &ndash; 2) y2 = x &ndash; 2 or y2 = 2 &ndash; x

Analytical Geometry> parabola...

Let V be the vertex and L be the latusrectum of the parabola x² = 2y + 4x – 4. Then the equation of the parabola whose vertex is at V, latusrectum is L/2 and axis is perpendicular to the axis of the given parabola.

(a) y² = x – 2

(b) y² = x – 4

(c) y² = 2 – x

(d) y² = 4 – x

Hrishant Goswami , 12 Years ago

Amit Saxena

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Analytical Geometry> parabola...

Let V be the vertex and L be the latusrectum of the parabola x2 = 2y + 4x – 4. Then the equation of the parabola whose vertex is at V, latusrectum is L/2 and axis is perpendicular to the axis of the given parabola. (a) y2 = x – 2 (b) y2 = x – 4 (c) y2 = 2 – x (d) y2 = 4 – x

Hrishant Goswami , 12 Years ago

Amit Saxena

LIVE ONLINE CLASSES

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The locus of the point represented by x= t^2 +t+1 and y=t^-t+1 is

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Let V be the vertex and L be the latusrectum of the parabola x² = 2y + 4x – 4. Then the equation of the parabola whose vertex is at V, latusrectum is L/2 and axis is perpendicular to the axis of the given parabola.

(a) y² = x – 2

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(d) y² = 4 – x