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Find the value of k such that (k-2)x +(k+3)y-5=0 is parallel to the line 2x-y+7=0

Akhil sai , 11 Years ago
Grade upto college level
anser 1 Answers
Sunil Kumar

Last Activity: 11 Years ago

k= -4/3 

The given lines :

2x-y+7=0 and (k-2)x+(k+3)y-5=0 are parallel. So, the slope (m) for both the lines will be same.

so we have , m=2 from 2x-y+7=0

Equating it with the slope of the second line we can find the value of k.

i.e. 2= (2-k)/(k+3)

k = -4/3 

 

Thanks & Regards
Sunil Kumar, 
askIITians Faculty
M.Sc., IIT Kharagpur

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