There is a point inside an equilateral triangle which is at a distance 1,2 and 3 from three sides . the area of triangle ________

Assume triangle to be ABC and point inside be P.Let each side be''a''.ar(ABC) = ar9PAB) +ar(PBC) + ar(PAC)Root3*a^2/4=1/2*a*1+1/2*a*2+1/2*a*3Get a and then the area.                                                                     Vinti SinghaiaskIITians Faculty,B.E(Honors) in Elec &Comm, Gold Medalist

First consider 🔺 ABC... Triangle ABC is an equilateral triangle.. Let the point inside the triangle be `P`.... According to Viviana`s theorem (search on internet for more details about theorem) sum of distance is equal to the height on equilateral triangle 🔺 which is 1+2+3=6.... Let the altitude meet base at point M.. In triangle AMB, by tan60=AM/BM...BM=2√3.. Total base (BC) is 2*BM..Hence BC=4√3.. Now, Area of triangle ABC = 1/2*BC*AM..Hence,area of triangle ABC 🔺 is 12√3.. .. Thanks for reading... 😊