Badiuddin askIITians.ismu Expert
Last Activity: 14 Years ago
Dear rohan
1\2(x2+y2)+ x cosA + y sinA - 4 = 0
or (x2+y2)+ 2x cosA + 2y sinA - 8 = 0
center of circle is (-cosA ,-sinA)
let center of circle is (h,k)
so h=-cosA and k=-sinA
h2+k2 =sin2A +cos2A
h2+k2 =1
so locus
x2+y2 =1
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