The common chord of x 2 + y 2 – 4x – 4y = 0 and x 2 + y 2 = 16 subtends at the origin an angle equal to (a) p /6 (b) p /4 (c) p /3 (d) p /2

Question

The common chord of x 2 + y 2 &ndash; 4x &ndash; 4y = 0 and x 2 + y 2 = 16 subtends at the origin an angle equal to (a) p /6 (b) p /4 (c) p /3 (d) p /2

Arun Kumar · Answer

They intersect orthogonally. Arun Kumar IIT Delhi Askiitians Faculty

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The common chord of x 2 + y 2 – 4x – 4y = 0 and x 2 + y 2 = 16 subtends at the origin an angle equal to (a) p /6 (b) p /4 (c) p /3 (d) p /2

The common chord of x² + y² – 4x – 4y = 0 and x² + y² = 16 subtends at the origin an angle equal to

        (a)    p/6

(b)    p/4

(c)    p/3

(d)    p/2

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The common chord of x 2 + y 2 – 4x – 4y = 0 and x 2 + y 2 = 16 subtends at the origin an angle equal to (a) p /6 (b) p /4 (c) p /3 (d) p /2

The common chord of x2 + y2 – 4x – 4y = 0 and x2 + y2 = 16 subtends at the origin an angle equal to (a) p/6 (b) p/4 (c) p/3 (d) p/2

1 Answers

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The common chord of x² + y² – 4x – 4y = 0 and x² + y² = 16 subtends at the origin an angle equal to

(a) p/6

(b) p/4

(c) p/3

(d) p/2