if a.,x1,x2 are in gp with common ratio r and b,y1,y2 are in gp with common ratio s and s-r=2 then the area of triangle with vertices (a''b),(x1,y1),(x2,y2) is

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Vikas TU · Answer

a.,x1,x2 and b,y1,y2 are in gp then we can say: 2x1 = a +x2 and also 2y1 = b + y2 or, a = 2x1 - x2 and b = 2y1 - y2 Hence, area of triangle with vertices (a,b),(x1,y1),(x2,y2) is Plz Approve! Plz Approve! Plz Approve!

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if a.,x1,x2 are in gp with common ratio r and b,y1,y2 are in gp with common ratio s and s-r=2 then the area of triangle with vertices (a''b),(x1,y1),(x2,y2) is

if a.,x1,x2 are in gp with common ratio r and b,y1,y2 are in gp with common ratio s and s-r=2 then the area of triangle with vertices (a''b),(x1,y1),(x2,y2) is

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if a.,x1,x2 are in gp with common ratio r and b,y1,y2 are in gp with common ratio s and s-r=2 then the area of triangle with vertices (a''b),(x1,y1),(x2,y2) is

if a.,x1,x2 are in gp with common ratio r and b,y1,y2 are in gp with common ratio s and s-r=2 then the area of triangle with vertices (a''b),(x1,y1),(x2,y2) is

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